array = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
array.reverse();
[array].reverse();
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
Array.reverse() | |
Array.toReversed() |
Test name | Executions per second |
---|---|
Array.reverse() | 55629256.0 Ops/sec |
Array.toReversed() | 32258364.0 Ops/sec |
The benchmark defined in the JSON compares the performance of two methods for reversing an array in JavaScript: Array.reverse()
and the proposed Array.toReversed()
, which utilizes the spread operator to create a new reversed array.
Array.reverse(): This method reverses the elements of the array in place, modifying the original array.
Array.toReversed(): This is not a standard JavaScript method (as of the last stable ECMAScript versions) but rather represents an alternative approach that involves spreading the original array into a new array and then reversing it.
Array.reverse()
due to the overhead of creating a new array and copying elements.Performance: The benchmark results show that Array.reverse()
executes approximately 1.7 times faster than the alternative using Array.toReversed()
. With Array.reverse()
achieving about 55.6 million executions per second compared to 32.3 million for Array.toReversed()
. Performance can greatly impact applications that require high-frequency data manipulation.
Use Cases:
Array.reverse()
is the optimal choice due to its efficiency. Array.toReversed()
would be preferable despite the performance trade-off.Array.reverse()
.In summary, the benchmark effectively showcases the trade-offs between performance and mutability in JavaScript's array manipulation. Understanding these differences helps developers choose the right method based on the specific needs of their applications.