let arr = [];
const fin = Number((Math.random() * 10).toFixed())
for (let i = 0; i <= fin; i++) { arr.push(i); }
for (let i = 0; i <= 10; i++) { /^(?:[-+]?(?:0|[1-9]\d*))$/.test(i); }
for (let i = 0; i <= 10; i++) { Number.isInteger(i); }
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
Regexp | |
isInteger |
Test name | Executions per second |
---|---|
Regexp | 5741349.0 Ops/sec |
isInteger | 156108128.0 Ops/sec |
Let's break down the provided benchmark and its results.
Benchmark Description
The benchmark compares two approaches to test whether a number is an integer: using a regular expression (Regexp
) versus using the Number.isInteger()
function in JavaScript.
Options Compared
Other Considerations
When choosing between these two approaches, consider the specific requirements of your use case:
Regexp
might be a better choice.Number.isInteger()
is likely a better option.Library Used
Neither of the two options relies on any external libraries. However, it's worth noting that modern JavaScript engines have built-in support for regular expressions, which can affect performance.
Special JS Features or Syntax
There are no special features or syntax used in these benchmark cases. The code is written in plain JavaScript.
Alternative Approaches
If you're looking for alternative approaches to test if a number is an integer, consider:
isNaN(Number(x))
can be used as an alternative to checking with isInteger()
or Regexp.Keep in mind that the performance of these alternatives might vary depending on your specific use case and JavaScript environment.
I hope this explanation helps you understand the benchmark and its results!