Array(10000).fill(1).reduce((acc, i, indx) => {acc[indx] = i; return acc;}, {});
Array(10000).fill(1).reduce((acc, i, indx) => {return {acc, [indx]: i}}, {});
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
Set | |
Spread |
Test name | Executions per second |
---|---|
Set | 13852.5 Ops/sec |
Spread | 100.9 Ops/sec |
Let's dive into the world of JavaScript microbenchmarks on MeasureThat.net.
Benchmark Definition
The provided JSON represents a benchmark definition for comparing two approaches to reducing an array: using concat()
with push
versus the new ES6 spread operator (...
). The benchmark aims to measure which approach is faster and more efficient.
Options Compared
Two options are being compared:
Array.prototype.concat()
method, which creates a new array by copying elements from an existing array, followed by assigning each element of the original array using the push()
method....
): This approach uses the spread operator to create a new object with key-value pairs from the original array.Pros and Cons
...
):Library Used
In this benchmark, no specific library is used. The focus is solely on comparing two JavaScript built-in methods.
Special JS Feature/Syntax
The ES6 spread operator (...
) is being tested. This feature was introduced in ECMAScript 2015 and allows for concise object creation from arrays or other iterables.
Other Alternatives
Before settling on these two approaches, developers might consider alternative methods:
Array.prototype.reduce()
without the spread operator to create a new array.Array.prototype.map()
followed by Object.fromEntries()
to transform the array into an object.Benchmark Preparation Code
The provided JSON does not include any script preparation code, suggesting that the benchmark is focused on measuring the performance difference between these two approaches in a vanilla JavaScript environment.