this.numberA = Math.random() * 1000;
this.numberB = Math.random() * 1000;
return Math.min(this.numberA, this.numberB);
if (this.numberA < this.numberB)
return this.numberA;
else
return this.numberB;
return (this.numberA < this.numberB) ? this.numberA : this.numberB
var min = this.numberB;
if (this.numberA < this.numberB) min = this.numberA;
return min;
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
Math.min | |
if | |
ternary | |
assing first |
Test name | Executions per second |
---|---|
Math.min | 68480408.0 Ops/sec |
if | 716771520.0 Ops/sec |
ternary | 715209408.0 Ops/sec |
assing first | 715834112.0 Ops/sec |
Let's break down the provided benchmark and its components.
Benchmark Definition JSON
The benchmark definition represents a single test case, which is to find the quickest operation to return the smaller of two numbers (this.numberA
and this.numberB
). The benchmark has four options:
Math.min()
to find the smallest number.? :
) to concisely express the same logic as the if/else
statement.this.numberA
to a variable min
and then updates min
if this.numberB
is smaller, finally returning the assigned value.Comparison
Math.min
.if/else
but likely slower than Math.min
. The ternary operator is also less readable than the traditional if/else
statement.Pros and Cons
if/else
.Library Usage
None of the provided options use a library specifically for this benchmark.
Special JavaScript Features or Syntax
None of the provided options utilize any special JavaScript features or syntax that would affect their performance or interpretation.
Now, let's talk about alternatives:
Keep in mind that the best approach for your benchmark will depend on your specific needs and goals.