this.numberA = Math.random() * 1000;
this.numberB = Math.random() * 1000;
return Math.min(this.numberA, this.numberB);
if (this.numberA < this.numberB)
return this.numberA;
else
return this.numberB;
return (this.numberA < this.numberB) ? this.numberA : this.numberB
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
Math.min | |
if | |
ternary |
Test name | Executions per second |
---|---|
Math.min | 92521624.0 Ops/sec |
if | 54536864.0 Ops/sec |
ternary | 55897128.0 Ops/sec |
Let's dive into the world of JavaScript microbenchmarks!
The provided JSON represents a benchmark test case on MeasureThat.net, which compares the performance of three different approaches to find the smaller of two numbers: Math.min()
, if/else
statements, and the ternary operator.
Options compared:
Pros and cons of each approach:
Library usage: None of the provided benchmark definitions explicitly use a library. However, MeasureThat.net itself relies on various libraries under the hood, such as WebKit for rendering and V8 for JavaScript execution.
Special JS feature/syntax: The ternary operator is an example of a shorthand syntax in JavaScript, which allows you to write a single expression that can be either true or false. This syntax is supported by most modern browsers, including Chrome.
Other alternatives:
If you want to explore other options for finding the smaller of two numbers, consider:
Math.max()
with -a
and -b
manipulationa < b ? -a : -b
)Keep in mind that these alternatives might have different performance characteristics or use cases, so it's essential to benchmark them against the original three approaches to see which one works best for your specific scenario.
Now, if you'll excuse me, I need to go grab some virtual coffee and breathe...