const a = [1, 2, 3, 4, 5];
const b = [1, 2, 4, 5, 3, 5];
a.every(x => b.some(y => x === y));
const a = [1, 2, 3, 4, 5];
const b = [1, 2, 4, 5, 3, 5];
for (let x of a) {
if (!b.some(y => x === y)) {
break;
}
}
const a = [1, 2, 3, 4, 5];
const b = [1, 2, 4, 5, 3, 5];
for (let i = 0; i < a.length; i++) {
if (!b.some(y => a[i] === y)) {
break;
}
}
const a = [1, 2, 3, 4, 5];
const b = [1, 2, 4, 5, 3, 5];
a.reduce((x, y, i) => i === 0 ? b.some(p => p === x) : b.some(p => p === y))
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
every | |
for of loop | |
for loop | |
reduce |
Test name | Executions per second |
---|---|
every | 112381608.0 Ops/sec |
for of loop | 77975248.0 Ops/sec |
for loop | 42828488.0 Ops/sec |
reduce | 120075280.0 Ops/sec |
Let's dive into the world of JavaScript microbenchmarks on MeasureThat.net.
Benchmark Definition
The provided JSON represents a benchmark with four test cases:
every
for of loop
for loop
reduce
Each test case is defined by a unique "Benchmark Definition" string, which contains the JavaScript code that will be executed.
Test Cases
Let's analyze each test case individually:
every
const a = [1, 2, 3, 4, 5];
const b = [1, 2, 4, 5, 3, 5];
a.every(x => b.some(y => x === y));
This test case uses the every()
method, which returns true
if all elements of an array pass a test provided as a function. The test is to check if every element in a
exists in b
.
Pros:
Cons:
some()
inside every()
for of loop
const a = [1, 2, 3, 4, 5];
const b = [1, 2, 4, 5, 3, 5];
for (let x of a) {
if (!b.some(y => x === y)) {
break;
}
}
This test case uses a for...of
loop to iterate over the elements of array a
. It breaks out of the loop as soon as it finds an element in b
that doesn't match any element in a
.
Pros:
every()
or some()
Cons:
every()
methodfor loop
const a = [1, 2, 3, 4, 5];
const b = [1, 2, 4, 5, 3, 5];
for (let i = 0; i < a.length; i++) {
if (!b.some(y => a[i] === y)) {
break;
}
}
This test case uses a traditional for
loop to iterate over the elements of array a
. It breaks out of the loop as soon as it finds an element in b
that doesn't match any element in a
.
Pros:
every()
or some()
Cons:
for...of
loop or the every()
methodreduce
const a = [1, 2, 3, 4, 5];
const b = [1, 2, 4, 5, 3, 5];
a.reduce((x, y, i) => i === 0 ? b.some(p => p === x) : b.some(p => p === y));
This test case uses the reduce()
method to iterate over the elements of array a
. It applies a callback function that checks if the current element exists in b
.
Pros:
Cons:
Other Alternatives
If you want to explore other alternatives, here are a few examples:
includes()
instead of some()
: b.includes(x)
for (let i = 0; i < a.length; i++) { ... }
every()
and some()
alternativesKeep in mind that the best approach depends on your specific use case, performance requirements, and personal coding style.
MeasureThat.net
The provided benchmark results show the execution times for each test case using Chrome 95. The "ExecutionsPerSecond" value represents the number of executions per second, which can be used to compare the performance of different approaches.
By analyzing these results, you can identify the most efficient approach for your specific use case and adjust your code accordingly.