var items = [{
val: 7
},
{
val: 9
},
{
val: 8
},
{
val: 3
},
{
val: 12
},
{
val: 34
},
{
val: 7
},
{
val: 512
}
]
Math.min(items.map(item => item.val))
items.reduce((acc, current) => acc < current.val ? acc : current.val)
items.reduce((acc, current) => acc < current.val ? acc : current.val, items[0].val)
items.sort((a, b) => a.val - b.val)[0].val
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
Map and Math.min | |
Reduce without initial value | |
Reduce with initial value | |
Sort and get first element |
Test name | Executions per second |
---|---|
Map and Math.min | 3617132.5 Ops/sec |
Reduce without initial value | 5092262.0 Ops/sec |
Reduce with initial value | 3695223.5 Ops/sec |
Sort and get first element | 3233399.0 Ops/sec |
Let's break down the provided JSON to understand what is being tested.
Benchmark Definition
The Script Preparation Code
defines an array of objects (items
) with a property val
. The script preparation code is executed once, and its output is not used in any way. This suggests that the benchmark is testing the execution time of various methods on this specific input data.
Individual Test Cases
There are four test cases:
map()
method to transform each object in the array into a single value (item.val
) and then passes these values to the Math.min()
function to find the minimum value.reduce()
method with an initial value set to items[0].val
. It iterates over each object in the array, comparing its val
property with the accumulator (acc
). If the current value is smaller than the accumulator, it updates the accumulator.reduce()
method with an initial value set to items[0].val
, just like the previous one. However, this time, no comparison is performed between the accumulator and the current value (acc < current.val ? acc : current.val
).sort()
method to sort the array of objects in ascending order based on their val
property. Then, it returns the val
property of the first element after sorting.Libraries and Special Features
Pros and Cons of Different Approaches
Other Alternatives
Some possible alternatives could include:
Array.prototype.every()
instead of Math.min()
: This would check if all elements in the array satisfy a certain condition (in this case, being greater than or equal to the initial value).minBy()
or sortBy()
functions.Keep in mind that these alternatives may introduce additional complexity and potentially alter the benchmark's results.