const larger = 10;
const smaller = 5;
[larger, smaller].sort((a,b) => b - a);
const larger = 10;
const smaller = 5;
[Math.max([smaller, larger]), Math.min([smaller, larger])];
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
sort | |
max/min |
Test name | Executions per second |
---|---|
sort | 25019020.0 Ops/sec |
max/min | 5219405.5 Ops/sec |
Let's break down the provided benchmark and explain what is being tested, compared, and their pros and cons.
Benchmark Definition
The benchmark definition represents two different approaches to compare the performance of:
sort()
method on an array containing two elements.Math.max()
and Math.min()
functions with an array containing two elements.These two approaches are being compared to determine which one is faster.
Options Compared
The options being compared are:
[a, b].sort((a, b) => b - a)
): This approach sorts the tuple in descending order and returns the larger element.Math.max([smaller, larger]), Math.min([smaller, larger])
): This approach uses the Math.max()
and Math.min()
functions to find the maximum and minimum elements in the array.Pros and Cons
In general, tuple sorting can be a good choice when working with small arrays or specific use cases where simplicity is prioritized. However, Math.max/min with array is often a better option for larger datasets or performance-critical code.
Library and Purpose
There are no libraries mentioned in the benchmark definition. The sort()
method and Math.max()
/Math.min()
functions are built-in JavaScript methods, making this benchmark more focused on the language's core functionality rather than third-party library optimizations.
Special JS Feature or Syntax
There is a special syntax used in the sort()
method: (a, b) => b - a
. This is an arrow function that takes two arguments and returns their difference. This syntax is a concise way to define small functions within the sorting callback, which can improve readability and maintainability.
Other Alternatives
Other alternatives for tuple sorting or Math.max/min with array could include:
Array.prototype.reduce()
for Math.max/min:const max = arr.reduce((a, b) => a > b ? a : b);
const min = arr.reduce((a, b) => a < b ? a : b);
Array.prototype.every()
and Array.prototype.some()
to find the maximum and minimum elements:const max = arr.every(x => x === Math.max(arr)) ? Math.max(arr) : null;
const min = arr.every(x => x === Math.min(arr)) ? Math.min(arr) : null;
These alternatives may offer different trade-offs in terms of performance, readability, and maintainability, depending on the specific use case.