const bool = true;
let i = 0;
let j = 0;
(() => {
if (bool) {
i++;
j = i + 1;
}
})();
(() => {
if (!bool) return;
i++;
j = i + 1;
})();
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
if true then | |
if not return |
Test name | Executions per second |
---|---|
if true then | 4442367.0 Ops/sec |
if not return | 4465844.5 Ops/sec |
The provided JSON and benchmark preparation code represent a JavaScript performance test comparing two conditional function calls based on the value of a boolean variable (bool
). The benchmark specifically tests how the JavaScript engine handles two different approaches to conditionals and evaluates their execution speed.
Benchmark Name: in function call: if true vs if not return
There are two test cases:
Test Case 1: "if true then"
(() => {
if (bool) {
i++;
j = i + 1;
}
})();
if
statement is executed because bool
is true
. This means that both i
is incremented, and j
is assigned a new value, i + 1
.Test Case 2: "if not return"
(() => {
if (!bool) return;
i++;
j = i + 1;
})();
bool
is not true. If it is false, the function returns early (exits without executing further) without modifying i
or j
. If it is true (which it is in this benchmark), the remaining lines execute.i++
and j = i + 1
), leading to changes in variable states.return
statement, effectively skipping the operations when bool
is false. This can sometimes be more performant in scenarios where the condition is frequently false.From the benchmark results:
While both test cases performed well, the first test case slightly lagged behind the second in terms of execution speed.
Test Case: "if true then"
bool
could frequently be false, it might result in unnecessary evaluations and state changes.Test Case: "if not return"
This benchmark explores the implications of straightforward conditional logic and its implications on execution speed. By evaluating the conditional execution paths, developers can better understand how to optimize code for performance based on conditional evaluations in JavaScript.