let arr = ['foo', 'bar', 'baz', 'foo1', 'bar1', 'baz1', 'foo2', 'bar2', 'baz2'];
arr = arr.slice();
const ret = arr.splice(3, 1);
let arr = ['foo', 'bar', 'baz', 'foo1', 'bar1', 'baz1', 'foo2', 'bar2', 'baz2'];
arr = arr.slice();
const ret = arr.slice(0, 3).concat(arr.slice(4));
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
splice | |
concat |
Test name | Executions per second |
---|---|
splice | 5398984.5 Ops/sec |
concat | 3165542.5 Ops/sec |
Let's break down the benchmark and explain what's being tested.
The benchmark is designed to compare two approaches: using splice()
or using slice()
followed by concat()
. The script preparation code and HTML preparation code are empty, which means that the test only focuses on the JavaScript code.
Test Cases
There are two individual test cases:
arr
with 9 elements, removes one element from the beginning of the array using splice(3, 1)
, and stores the result in a variable ret
.arr
with 9 elements, removes one element from the beginning of the array using slice(0, 3)
(which returns a new array with the first 3 elements), concatenates this new array with another array created by taking the remaining elements of arr
using slice(4)
, and stores the result in a variable ret
.Library Usage
Neither test case uses any external libraries. The splice()
and concat()
methods are built-in JavaScript functions.
Special JavaScript Features/Syntax
There are no special JavaScript features or syntax used in these test cases. They only rely on standard JavaScript operations (array creation, indexing, slicing, and concatenation).
Approaches Compared
The two approaches being compared are:
splice()
.slice(0, 3)
, concatenates this new array with another array created by taking the remaining elements of the original array using slice(4)
.Pros and Cons
Here are some pros and cons of each approach:
splice
Pros:
Cons:
concat(): slice().concat()
Pros:
Cons:
Considerations
When choosing between splice()
and concat(): slice().concat()
, consider the following factors:
splice()
might be a better choice. For larger arrays or when preserving the original array's integrity, concat(): slice().concat()
might be more suitable.Other Alternatives
There are other alternatives you can consider:
with
...: Using the spread operator (
...`) can create a new array while preserving the original array's indices.for...of
loops or Array.prototype.forEach()
to remove elements from an array without modifying it.Keep in mind that these alternatives might have different performance characteristics, so test them thoroughly to determine which one best fits your needs.