this.number = Math.random() * 1000
return Math.max(501, this.number)
return this.number >= 501 ? this.number : 0
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
Math.max | |
ternary |
Test name | Executions per second |
---|---|
Math.max | 98851704.0 Ops/sec |
ternary | 74142632.0 Ops/sec |
Let's break down the provided benchmark and its results to understand what's being tested and compared.
Benchmark Definition
The benchmark definition consists of two test cases:
return Math.max(501, this.number)
return this.number >= 501 ? this.number : 0
These test cases are comparing the performance of the Math.max
function versus a ternary operator (ternary
) that achieves similar functionality.
Options Compared
The two options being compared are:
Math.max(501, this.number)
: This is a built-in JavaScript function that returns the maximum value between two arguments.this.number >= 501 ? this.number : 0
: This is a ternary operator that checks if this.number
is greater than or equal to 501 and returns either this.number
or 0 based on the condition.Pros and Cons of Each Approach
Math.max(501, this.number)
:this.number >= 501 ? this.number : 0
(ternary operator):Library Usage
There is no explicit library usage mentioned in the benchmark definition. However, it's worth noting that this.number
suggests that the test is running within an object context, and this
refers to the current object being tested.
Special JS Features/Syntax
The only special feature or syntax used here is the ternary operator (? :
), which allows for a single expression to be evaluated with multiple conditions. This is a common JavaScript construct that can simplify code but may also make it less readable in certain situations.
Other Alternatives
For this specific test case, other alternatives could include:
Math.min(501, this.number)
to find the smaller of the two values.return (this.number > 500) ? this.number : 0
).However, the ternary operator and Math.max
are likely to be the most straightforward alternatives in this case.