const f = (a, ...b) => a.concat(b.map(String))
const r = f([0], ...[1, 2, 3, 4, 5]);
const f = (a, b) => a.concat(b.map(String))
const r = f([0], [1, 2, 3, 4, 5]);
FAQ: FAQ
Source code: GitHub/MeasureThat.net
Report issues: MeasureThat.net/Issues
Based on: Benchmark.js
Facebook page: https://www.facebook.com/MeasureThat.Net
Python benchmarks support: Pyodide