Run results for: bracket balance algorithm

Run details:

User agent: Mozilla/5.0 (Macintosh; Intel Mac OS X 10_14_0) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/70.0.3538.77 Safari/537.36

Browser: Chrome 70

Operating system: Mac OS X 10.14.0

Device Platform: Desktop

Date tested: 5 years ago

Tests:

split - join
isBalanced1 = (s, o, v, rx1, rx2) => { rx1 = /[^\{\}\[\]]/g; rx2 = /\[\]|\{\}|/g; v = ['()', '{}', '[]', '']; o = s.replace(rx1, ''); for (let i = 0; i < o.length; i += 0.5) { o = o.split(rx2).join``; } return v.includes(o); }; const test = '[[[{{{((()))}}}]]]'; console.log(isBalanced1(test));
replace
isBalanced2 = (s, o, v, rx1, rx2) => { rx1 = /[^\{\}\[\]]/g; rx2 = /\[\]|\{\}|/g; v = ['()', '{}', '[]', '']; o = s.replace(rx1, ''); for (let i = 0; i < o.length; i += 0.5) { o = o.replace(rx2, ''); } return v.includes(o); }; const test = '[[[{{{((()))}}}]]]'; console.log(isBalanced2(test));
slice and concat
isBalanced3 = (s, o, v, rx1, rx2) => { rx1 = /[^\{\}\[\]]/g; rx2 = /\[\]|\{\}|/g; v = ['()', '{}', '[]', '']; o = s.replace(rx1, ''); for (let i = 0; i < o.length; i++) { if (v.includes(`${o[i]}${o[i + 1]}`)) { o = o.slice(0, i).concat(o.slice(i + 2, o.length)); i -= 2; } } return v.includes(o); }; const test = '[[[{{{((()))}}}]]]'; console.log(isBalanced3(test));