var arr = [];
var i = 0;
while (i <= 1E5) arr[i] = i++;
const item = !!arr.find(item => item == 1E5);
const index = arr.findIndex(item => item == 1E5) > -1;
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
Array.prototype.find | |
Array.prototype.findIndex |
Test name | Executions per second |
---|---|
Array.prototype.find | 1950.5 Ops/sec |
Array.prototype.findIndex | 1897.9 Ops/sec |
Let's break down the provided benchmark definition and test cases to understand what's being tested.
Benchmark Definition:
The benchmark is testing two methods on the Array prototype:
find
: Returns the value of the first element in an array that satisfies the provided testing function.findIndex
: Returns the index of the first element in an array that satisfies the provided testing function, or -1 if no element satisfies it.Options Compared:
The benchmark is comparing the performance of these two methods:
Array.prototype.find
Array.prototype.findIndex
Pros and Cons of Different Approaches:
Both methods have their pros and cons:
find
:findIndex
:find
, as it returns -1 if no element matches, whereas find
returns the first matched element.Library:
None are used in this benchmark.
Special JS Feature/Syntax:
The testing function for both methods uses a shorthand method to check if an element is equal to 1E5 (item == 1E5
). This syntax is valid JavaScript but is more commonly used in strict mode or with explicit type checking. In standard JavaScript, it's written as item === 1E5
or item == 1E5
(note the loose equality).
Other Alternatives:
For these specific methods, other alternatives are:
find
and findIndex
, you could use other methods like some()
or every()
.Array.prototype.some()
or Array.prototype.every()
, which can be faster for large arrays.for
loop.Keep in mind that the best approach depends on your specific use case and requirements.