const a = [1, 2, 3, 4, 5];
const b = [1, 2, 4, 5, 3, 5];
a.every(x => b.some(y => x === y));
const a = [1, 2, 3, 4, 5];
const b = [1, 2, 4, 5, 3, 5];
for (let x of a) {
if (!b.some(y => x === y)) {
break;
}
}
const a = [1, 2, 3, 4, 5];
const b = [1, 2, 4, 5, 3, 5];
for (let i = 0; i < a.length; i++) {
if (!b.some(y => a[i] === y)) {
break;
}
}
const a = [1, 2, 3, 4, 5];
const b = [1, 2, 4, 5, 3, 5];
a.reduce((x, y, i) => i === 0 ? b.some(p => p === x) : b.some(p => p === y))
const a = [1, 2, 3, 4, 5];
const b = [1, 2, 4, 5, 3, 5];
a.reduce(function (x, y, i) {
return i === 0 ? b.some(p => p === x) : b.some(p => p === y)
})
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
every | |
for of loop | |
for loop | |
reduce | |
reduce 2 |
Test name | Executions per second |
---|---|
every | 85181024.0 Ops/sec |
for of loop | 54940000.0 Ops/sec |
for loop | 32854398.0 Ops/sec |
reduce | 97258496.0 Ops/sec |
reduce 2 | 97750032.0 Ops/sec |
Let's break down the JavaScript microbenchmarks on MeasureThat.net and explain what's being tested.
The benchmark definition is provided in JSON format, which includes four different test cases:
array every vs some vs for loop fork
every()
, some()
, and a traditional for
loop to find if an element exists in another array.reduce
reduce 2
(a variant of the previous one)every
for of loop
for loop
Let's analyze each test case:
Test Case 1: array every vs some vs for loop fork
This test case compares four approaches to find if an element exists in another array:
every()
: The every()
method returns true
if all elements of the given array pass the test implemented by the provided function.some()
: The some()
method returns true
if at least one element of the given array passes the test implemented by the provided function.for
loop: A manual loop that iterates over each element in the first array and checks if it exists in the second array using the in
operator or a conditional statement.Pros and Cons:
every()
:some()
:every()
, as it only requires one match.for
loop:Individual Test Cases
reduce()
reduce()
method applies a function against an accumulator and each element in the array (from left to right) to reduce it to a single value.reduce 2
every
(already analyzed above)for of loop
for...of
loop that iterates over each element in the array and checks if it exists in another array using the same logic as the traditional for
loop.Pros and Cons:
reduce()
:for of loop
:for...of
loop syntax.Other Considerations
When choosing between these approaches, consider the following:
reduce()
or traditional for
loops might be faster due to their optimized iteration logic. However, if you only need to check for a single element, every()
or some()
might be more efficient.every()
and some()
provide concise, expressive solutions that are easier to understand and write than traditional loops. reduce()
can also be readable, but it may require some familiarity with this method.Alternative Approaches
Other approaches you could consider using in JavaScript include:
includes()
method: Instead of checking for an element's existence using the in
operator or a conditional statement, you can use the includes()
method to check if an array contains a specific value.filter()
, map()
, or forEach()
might be more suitable.I hope this helps! Do you have any specific questions about these approaches?