var a = [
'height',
'width',
'maxHeight',
'maxWidth',
'maxHeight',
'minWidth',
'color',
'bg',
'backgroundColor',
'opacity',
'm',
'mt',
'mb',
'mr',
'mr',
'mx',
'my',
'p',
'pt',
'pb',
'pr',
'pl',
'px',
'py',
'border',
'boxShadow',
'flex',
'verticalAlign',
'textAlign',
'overflow',
'display',
'cursor'
];
var b = new Set(a)
return a.includes(a[Math.floor(Math.random() * a.length)])
return b.has(a[Math.floor(Math.random() * a.length)])
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
arr.includes | |
set.has |
Test name | Executions per second |
---|---|
arr.includes | 4093985.2 Ops/sec |
set.has | 4125132.8 Ops/sec |
Benchmark Explanation
The provided benchmark compares the performance of two JavaScript methods: array.includes()
and set.has()
. The test is designed to measure which method is faster when searching for an element in an array or a set, respectively.
Options Compared
Two options are compared:
Pros and Cons of Each Approach
Library Used
The Set
object is used in the benchmark. A set is an unordered collection of unique values, which makes it suitable for this test case.
Special JS Feature or Syntax
None mentioned in this specific test case.
Other Considerations
This benchmark is relevant for developers working with JavaScript and may be useful when deciding between array.includes()
and set.has()
for performance-critical applications. Additionally, understanding the trade-offs between these two methods can help optimize code for different use cases.
Alternatives
Some alternative approaches to this test case might include:
Map
data structure instead of a set, this method checks if a specified value exists in the map.These alternatives would require modifications to the benchmark test case and may not directly compare to the original test.