var array = Array.from(Array(100).keys());
var newElement = 888
array.unshift(newElement)
array = [newElement].concat(array)
array = [newElement, array]
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
Unshift | |
Concat | |
Spread |
Test name | Executions per second |
---|---|
Unshift | 34551.7 Ops/sec |
Concat | 987.8 Ops/sec |
Spread | 189.2 Ops/sec |
Let's break down the provided JSON and explain what's being tested, compared, and some pros and cons of different approaches.
Benchmark Definition
The benchmark definition represents a JavaScript microbenchmark that tests the performance of adding an item to the first position in an array. The script preparation code initializes an array with 100 elements from 0 to 99 using Array.from(Array(100).keys())
and assigns a new value newElement = 888
to a variable.
Test Cases
The benchmark has three test cases:
unshift()
method to add the new element to the beginning of the array.concat()
method to concatenate an array with a single-element array containing the new element, and then assigns the result back to the original array....
) to add the new element to the beginning of the array.Library and Purpose
None of these test cases rely on any external libraries.
Special JS Feature/Syntax
There's no special JavaScript feature or syntax being used in these test cases. They are using standard methods and operators available in modern JavaScript.
Pros and Cons of Different Approaches
unshift()
method.unshift()
.unshift()
and concat()
, but a good alternative if you want to explore other methods.Other Alternatives
If you wanted to test other approaches for adding an element to the beginning of an array, you could consider:
Array.prototype.push()
: This would be less efficient than unshift()
due to the need to shift elements after inserting a new one.Array.prototype.splice()
: This would also be less efficient than unshift()
, as it involves more operations and checks.Keep in mind that these alternatives may not be supported in older browsers or versions of JavaScript, so make sure to test them thoroughly if you decide to use them.