("this is foo bar".match(/o/g)||[]).length
"this is foo bar".split("o").length-1
var stringsearch = "o";
var str = "this is foo bar";
for(var count=-1,index=-2; index != -1; count++,index=str.indexOf(stringsearch,index+1) );
var stringsearch = "o";
var str = "this is foo bar";
for(var i=count=0; i<str.length; count+=+(stringsearch===str[i++]));
var str = "this is foo bar";
str.length - str.replace(/o/g,'').length;
var str = "this is foo bar";
var schar = 'o';
var hist={};
for(si in str){
hist[str[si]] = hist[str[si]] ? 1+hist[str[si]]:1;
}
var str = "this is foo bar";
var char = 'o';
var count = 0;
for (let c in str) {
if (str[c] === char) count++;
}
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
regex | |
split | |
for loop1 | |
for loop 2 | |
deleting | |
histogram | |
for in |
Test name | Executions per second |
---|---|
regex | 4693308.0 Ops/sec |
split | 6017223.0 Ops/sec |
for loop1 | 11054253.0 Ops/sec |
for loop 2 | 187614.0 Ops/sec |
deleting | 5546296.5 Ops/sec |
histogram | 68407.8 Ops/sec |
for in | 209206.4 Ops/sec |
Let's break down the provided benchmark and explain what's being tested, compared, and their pros and cons.
Benchmark Definition
The benchmark is defined by a JSON object with several properties:
Name
: a unique name for the benchmarkDescription
: an optional description of the benchmark (not filled in this case)Script Preparation Code
and Html Preparation Code
: optional code that can be executed before running the benchmark (also not filled in this case)Individual Test Cases
The benchmark consists of six test cases, each with a unique Benchmark Definition
:
(\"this is foo bar\".match(/o/g)||[]).length
"this is foo bar".split("o").length-1
indexOf()
.str.length - str.replace(/o/g,'').length
Comparing Approaches
The test cases compare different approaches to counting the number of occurrences of a specific character ("o") in a string:
indexOf()
or conditional increment to find the character "o" in a string, respectively. These approaches have varying levels of efficiency due to their implementation details (e.g., loop overhead, branch prediction).replace()
to remove all occurrences of "o" from the string and then subtracts the length of the resulting string from the original string length to get the count.Pros and Cons
Here's a brief summary of the pros and cons of each approach:
Other Alternatives
Some alternative approaches could include:
Array.prototype.filter()
or Array.prototype.every()
to create an array of indices where the character "o" appears, and then returning the length of this array.String.prototype.search()
or String.prototype.lastIndexOf()
, to find the first or last occurrence of "o".Keep in mind that these alternatives may have varying levels of complexity and overhead compared to the existing test cases.