var obj = {
foo: 1,
bar: 2,
}
if (obj.foo) delete obj.foo;
const {foo, rest} = obj;
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
delete | |
deconstruct |
Test name | Executions per second |
---|---|
delete | 12473766.0 Ops/sec |
deconstruct | 1589643.9 Ops/sec |
Let's dive into the world of JavaScript microbenchmarks on MeasureThat.net.
What is tested:
The provided benchmark tests two different approaches for deleting properties from an object in JavaScript:
delete
operator: This approach uses the delete
keyword to remove a property from an object.{ foo, ...rest } = obj;
to extract values from an object and then ignore certain properties.Options compared:
The benchmark compares two options:
delete
Pros and Cons of each approach:
delete
operator:delete
keyword.delete
operator due to reduced overhead.Library usage:
In the provided benchmark definition, there is no explicit library usage. However, if a test case uses a library, it's likely that the library is being used to create or manipulate objects, and the focus of the benchmark is on the performance difference between delete
and deconstruction.
Special JS feature or syntax:
The benchmark uses ES6 syntax for destructuring assignment (const {foo, ...rest} = obj;
). This syntax requires support for ES6 modules and object destructuring in the target browser. The test case assumes that the browser supports this syntax and ignores any potential compatibility issues.
Other alternatives:
If you wanted to explore alternative approaches for deleting properties from an object, some other options might include:
Object.defineProperty()
with deleteProperty()
: This approach uses the defineProperty()
method to set a property's descriptor, then uses the deleteProperty()
method to delete the property.Keep in mind that each of these alternatives has its own trade-offs and potential performance implications. The benchmark on MeasureThat.net is focused specifically on comparing the delete
operator and deconstruction using destructuring assignment.