function shuffle(array) {
var currentIndex = array.length, temporaryValue, randomIndex;
// While there remain elements to shuffle...
while (0 !== currentIndex) {
// Pick a remaining element...
randomIndex = Math.floor(Math.random() * currentIndex);
currentIndex -= 1;
// And swap it with the current element.
temporaryValue = array[currentIndex];
array[currentIndex] = array[randomIndex];
array[randomIndex] = temporaryValue;
}
return array;
}
var sorted = [];
var shuffled = [];
for (var i = 0; i < 1000; i++) {
sorted.push('a' + i);
shuffled.push('a' + i);
}
shuffled = shuffle(shuffled);
var s2 = sorted.sort();
var s2 = shuffled.sort();
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
Sort the sorted | |
Sort the shuffled |
Test name | Executions per second |
---|---|
Sort the sorted | 3066.3 Ops/sec |
Sort the shuffled | 2980.2 Ops/sec |
Overview of the Benchmark
The provided JSON represents a JavaScript microbenchmarking test case designed to compare the performance of the built-in sort()
method on two types of arrays: an already sorted array and a randomly shuffled array.
Options Compared
Two options are being compared:
sort()
method is when given an array that is already in ascending order.sort()
method is when given an array that has been randomly shuffled.Pros and Cons of Each Approach
Already Sorted Array:
Randomly Shuffled Array:
Other Considerations
The benchmark uses a simple shuffling algorithm (shuffle()
function) to create the randomized array. This is sufficient for this specific test case but might not be efficient enough for more complex scenarios.
Library Used
There doesn't seem to be any external library used in this benchmarking test case.
Special JS Feature or Syntax (None)
No special JavaScript features or syntax are being tested or utilized in this benchmark.
Alternative Approaches
Other alternatives could include:
sort()
method, which has varying performance characteristics depending on the browser and JavaScript engine, using an external sorting library like QuickSort or Merge Sort.sort()
method under heavier loads.By exploring these alternative approaches, you can gain a deeper understanding of the performance characteristics of the sort()
method and make more informed decisions about when to use it in your own code.