Benchmark: exercism-pangram-bench

Tests:

Loop over characters, check if in input Set
function isPangram(str) { const s = new Set(str.toLowerCase()) let a = 97 for (let i = 0; i < 26; i++) { if (!s.has(String.fromCharCode(a + i))) return false } return true } console.log(isPangram('the quick brown fox jumps over the lazy dog'))
Flip object keys
function isPangram (str) { let a = 97 let seen = {} for (let i = 0; i < 26; i++) { seen[String.fromCharCode(a + i)] = false } str.toLowerCase().split('').map(char => (seen[char] = true)) return Object.values(seen).every(val => val) } console.log(isPangram('the quick brown fox jumps over the lazy dog'))
Compare two sets (generate letterSet)
function isPangram (str) { let a = 97 let letterSet = new Set() for (let i = 0; i < 26; i++) { letterSet.add(String.fromCharCode(a + i)) } const inputSet = new Set(str.replace(/[^a-zA-Z]/g, '').toLowerCase()) return letterSet.size === inputSet.size } console.log(isPangram('the quick brown fox jumps over the lazy dog'))
Compare two sets (static letterSet)
function isPangram (str) { let letterSet = new Set('abcdefghijklmnopqrstuvwxyz') const inputSet = new Set(str.replace(/[^a-zA-Z]/g, '').toLowerCase()) return letterSet.size === inputSet.size } console.log(isPangram('the quick brown fox jumps over the lazy dog'))

Rendered benchmark preparation results:

Previous results

Test case name	Result
Loop over characters, check if in input Set
Flip object keys
Compare two sets (generate letterSet)
Compare two sets (static letterSet)

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exercism-pangram-bench (version: 0)