array = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15];
array.reverse();
array.toReversed();
array.slice().reverse();
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
Array.reverse() | |
Array.toReversed() | |
Array.slice.reverse() |
Test name | Executions per second |
---|---|
Array.reverse() | 46719268.0 Ops/sec |
Array.toReversed() | 17090602.0 Ops/sec |
Array.slice.reverse() | 29164310.0 Ops/sec |
The benchmark defined in the provided JSON compares the performance of three different methods for reversing an array in JavaScript: Array.reverse()
, Array.toReversed()
, and Array.slice().reverse()
. Each method is tested to see how many times it can be executed per second, which gives us a measure of its performance efficiency.
Array.reverse()
Array.toReversed()
Array.slice().reverse()
Array.slice()
and then reverses the copied array in place with Array.reverse()
.Array.toReversed()
, it preserves the original array, making it suitable for cases where you want to keep the original order intact.slice()
) and then reversing it, which can lead to increased memory use and decreased performance compared to direct in-place reversal.From the benchmarking results, it is evident that Array.reverse()
is the most performant method for reversing arrays when in-place modification is acceptable. In contrast, if immutability is necessary, Array.toReversed()
is preferred, albeit with a trade-off in performance. Array.slice().reverse()
provides a middle ground but incurs the overhead of creating an extra array.
While the three methods tested are conventional, other alternatives might include:
Overall, selecting the right method for reversing an array in JavaScript largely depends on the specific performance requirements and constraints of the application being developed, particularly regarding whether or not the original array should remain unchanged.