var jsonString = '{"user":{"id":1,"name":{"first":"太郎","last":"山田"},"age":30,"email":"taro.yamada@example.com","address":{"street":"1-2-3","city":"東京","prefecture":"東京都","postalCode":"100-0001"},"phoneNumbers":[{"type":"mobile","number":"090-1234-5678"},{"type":"home","number":"03-1234-5678"}],"hobbies":[{"name":"サッカー","level":"中級"},{"name":"読書","genres":["フィクション","ノンフィクション","ミステリー"]},{"name":"料理","skills":{"cuisine":["和食","イタリアン"],"level":"上級"}}],"preferences":{"language":"日本語","notifications":{"email":true,"sms":false,"push":true}}}}'
var dummy = JSON.parse(jsonString);
eval('var dummy = ' + jsonString);
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
JSON.parse() | |
eval() |
Test name | Executions per second |
---|---|
JSON.parse() | 675628.0 Ops/sec |
eval() | 765278.7 Ops/sec |
The benchmark provided compares the performance of two methods for parsing a large JSON object in JavaScript: JSON.parse()
and eval()
. Here's a detailed explanation of the tests being conducted, the libraries and methodologies involved, as well as the performance characteristics of each approach.
Benchmark #1: JSON.parse()
JSON.parse()
to convert a string containing JSON data into a JavaScript object. Benchmark #2: eval()
eval()
function, which takes a string and executes it as JavaScript code. The test string is prefixed with 'var dummy = '
to create a JavaScript variable on the fly.eval()
can lead to security concerns, especially if the input is not trusted, as it may allow execution of arbitrary code.JSON.parse()
because it requires the JavaScript engine to evaluate the string as code rather than just parsing it as JSON.From the benchmark results:
eval()
performed better, executing 765,278.69 operations per second.JSON.parse()
was slightly slower, with 675,628.0 operations per second.JSON.parse()
and eval()
often depends on the context of the application. For most scenarios involving JSON data, JSON.parse()
is highly preferred due to its safety and performance.json2.js
or fast-json-parse
) can be employed to further enhance JSON parsing speed.JSON.parse()
is favored, while eval()
should be avoided unless absolutely necessary and safe.In summary, the benchmark provides a clear comparison between the two methods of parsing JSON data in JavaScript. Most use cases will benefit from the safer and faster JSON.parse()
, while eval()
can be considered when flexibility is needed but should come with caution due to associated security risks. Understanding these trade-offs helps software engineers make informed decisions based on the specific requirements and contexts of their applications.