Benchmark: sort() vs reverse() when getting last item or first item

Tests:

first item after reverse
array.forEach(n => { const repeat = Math.sqrt(n); const result = [[], []]; for (let i = 1; i <= repeat; i++) { if(n % i === 0) { result.push(i); if (i !== repeat) result.push(n / i); } } result.sort().reverse()[0] } )
last item after sort
array.forEach(n => { const repeat = Math.sqrt(n); const result = [[], []]; for (let i = 1; i <= repeat; i++) { if(n % i === 0) { result.push(i); if (i !== repeat) result.push(n / i); } } result.sort()[result.length-1] } )

Rendered benchmark preparation results:

Previous results

Test case name	Result
first item after reverse
last item after sort

Latest run results:

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sort() vs reverse() when getting last item or first item (version: 1)