String.prototype.replaceAll = function(search, replacement) {
var target = this;
return target.replace(new RegExp(search, 'g'), replacement);
};
"this is it".replace(/ /g, "+");
"this is it".split(" ").join("+");
"this is it".replaceAll(" ", "+");
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
replace regex | |
split-join | |
replaceAll |
Test name | Executions per second |
---|---|
replace regex | 4159540.2 Ops/sec |
split-join | 3587522.0 Ops/sec |
replaceAll | 1239270.9 Ops/sec |
Overview of the Benchmark
The provided benchmark tests three different approaches to perform a string replacement: split-join
, regex replace
, and replaceAll
. The goal is to determine which approach is the most efficient.
Options Compared
replaceAll
from the JavaScript prototype chain.Pros and Cons
Library Usage
There is no explicit library mentioned in the provided code. However, it's essential to note that replaceAll
uses a custom method, which might be influenced by the underlying JavaScript engine or browser. If you were to implement this on your own, you would likely use a similar approach as the one shown in the "Script Preparation Code".
Special JS Feature or Syntax
There is no special JavaScript feature or syntax used in this benchmark.
Other Alternatives
Some alternative approaches that might be worth considering include:
map()
to transform an array of characters into a new string by applying a lambda function to each element, and then joining the resulting array with the specified delimiter.These alternatives might offer different trade-offs in terms of performance, readability, or ease of implementation. However, without additional context or requirements, it's difficult to recommend one over the others.
Keep in mind that the benchmark's primary goal is to compare the performance of these three approaches. The choice of alternative approach ultimately depends on your specific use case and priorities.
Here's a simple example of how you could modify the "replace regex" test case using String.prototype.replace()
:
{
"Benchmark Definition": "\"this is it\".replace(/ /g, '+');",
"Test Name": "replace"
}
This will yield similar results as the original "replace regex" test case but might be slightly faster due to the optimized implementation of String.prototype.replace()
.