"test\u0000test\u0000test".replaceAll("\u0000", "!BAD!")
"test\u0000test\u0000test".replaceAll(/\u0000/g, "!BAD!")
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
string | |
regex |
Test name | Executions per second |
---|---|
string | 12895741.0 Ops/sec |
regex | 2933097.2 Ops/sec |
Let's dive into the world of MeasureThat.net and explore the benchmark you provided.
What is being tested?
The benchmark measures two approaches to replacing whitespace characters (\u0000
) with a string "!BAD!"
in a given input string. The two approaches are:
.replaceAll()
method, which replaces all occurrences of a specified value (in this case, \u0000
) with another value (in this case, "!BAD!"
)./\\u0000/g
) to replace all occurrences of whitespace characters (\u0000
) with the string "!BAD!"
.Options being compared
The benchmark is comparing the performance of these two approaches:
.replaceAll()
/\\u0000/g
Pros and Cons
Here are some pros and cons for each approach:
Library/Regex
In this benchmark, a regular expression is used (\\u0000
) to match whitespace characters. The /g
flag at the end of the regex pattern indicates that all occurrences should be replaced, not just the first one.
Special JS feature/Syntax
There isn't any special JavaScript feature or syntax being tested in this benchmark. It's purely focused on comparing two basic string replacement approaches.
Other alternatives
If you want to test other approaches, here are some alternative methods:
string-escape
or regex-optimize
to optimize regex patterns for performance.String.prototype.replace()
or String.prototype.normalize()
to replace whitespace characters.Keep in mind that the best approach will depend on your specific use case and requirements.