var test = [];
for (let i = 0; i < 100000; i++) {
test.push(i);
}
for (let i = 0; i < test.length; i++) {
test[i] = i * 2;
}
const copyTest = [];
for (let i = 0; i < test.length; i++) {
const currentItem = test.shift();
copyTest.push(currentItem * 2);
}
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
Mutate array | |
Memory efficient map |
Test name | Executions per second |
---|---|
Mutate array | 85.0 Ops/sec |
Memory efficient map | 15264040.0 Ops/sec |
Let's dive into the world of JavaScript microbenchmarks on MeasureThat.net.
Benchmark Definition
The provided benchmark definition represents a comparison between two approaches:
test
array.map()
method to create a new array with modified values without altering the original array. Instead, it creates a copy of the original array using shift()
, modifies the copied array, and then pushes the modified elements back into the copyTest
array.Options Compared
The two approaches are being compared in terms of their performance:
Pros and Cons
Here's a brief analysis of the pros and cons for each approach:
map()
method and its behaviorLibrary or Special JS Feature
The benchmark uses the map()
method, which is a built-in JavaScript function that creates a new array by performing an operation on each element of an existing array. The shift()
method is also used to remove elements from the original array and return them as an array.
There are no special JavaScript features or syntax mentioned in this benchmark definition.
Alternatives
If you're interested in exploring alternative approaches, here are a few options:
map()
or modifying arrays directly, you could create a custom function that mutates the original array by applying the desired transformation.For this specific benchmark, MeasureThat.net is providing a straightforward comparison between two approaches. You can use the insights gained from this benchmark to inform your own coding decisions when working with JavaScript arrays.