var params = [ "hello", true, 7 ]
var other = [ 'new', params ]
var params = [ "hello", true, 7 ];
params.unshift('new');
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
Spread | |
Unshift |
Test name | Executions per second |
---|---|
Spread | 57376580.0 Ops/sec |
Unshift | 20134590.0 Ops/sec |
Let's break down the provided benchmark and explain what's being tested, compared, and analyzed.
Benchmark Overview
The benchmark compares two approaches for adding a new element to an array: using the unshift
method versus destructuring with the spread operator (...
).
Options Compared
There are two options being compared:
...
): This approach uses the spread operator to create a new array by copying elements from the original array and adding a new element.Pros and Cons
...
):unshift
for large arrays, more concise and expressive code.Library/Tool Used
There doesn't appear to be any specific library or tool being used in this benchmark. However, the use of the spread operator (...
) requires modern JavaScript features, which is not a library per se but rather a feature of the JavaScript language.
Special JS Feature/Syntax
The use of the spread operator (...
) and destructuring are examples of modern JavaScript features introduced with ES6+. These features provide concise and expressive ways to create new arrays and objects from existing ones.
Other Considerations
unshift
and destructuring with the spread operator can be significant for large arrays. In this benchmark, the raw execution time is provided, but actual performance may vary depending on specific use cases.unshift
is simple and easy to read, destructuring with the spread operator can make code more concise and expressive. However, readability also depends on individual developer preferences.Other Alternatives
If you were to replace this benchmark with alternative approaches, some options could be:
concat()
: This method creates a new array by copying elements from an existing array and adding one or more elements.Array.prototype.push()
followed by shift()
: This approach adds a new element to the end of the array using push()
, then removes the last element using shift()
.Keep in mind that the choice of alternative approaches depends on your specific use case and performance requirements.