var a = [];
var b = new Map()
for(let i = 0; i < 100000; i++){
a.push(i);
b.set(i, Math.random());
}
return a.includes(Math.floor(Math.random()*100000))
return b.has(Math.floor(Math.random()*100000))
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
includes | |
lookup |
Test name | Executions per second |
---|---|
includes | 21757.3 Ops/sec |
lookup | 2182811136.0 Ops/sec |
Let's break down the provided benchmark definition and test cases.
What is tested?
The main difference between two approaches: using array.includes()
versus Map.has()
. Both methods are used to check if an element exists in a collection (an array or a Map, respectively).
Options being compared
There are two options:
array.includes()
: A method that checks if an element is present in the given array. It returns true
if the element is found and false
otherwise.Map.has()
: A method on the Map object that checks if a key (element) exists in the map.Pros and Cons of each approach
array.includes()
Map.has()
array.includes()
for large datasets, as it uses a hash table lookup.Library used
In this benchmark, the Map
object is used from the ECMAScript standard library.
Special JS feature or syntax
None mentioned in the provided test cases. However, it's worth noting that Map.has()
is a relatively new feature introduced in ECMAScript 2015 (ES6) and was not widely supported until recent browsers and JavaScript engines adopted it.
Other considerations
When choosing between array.includes()
and Map.has()
, consider the following:
Map.has()
might be a better choice due to its performance advantages.Other alternatives
If you can't use Map.has()
, other alternatives for checking if an element exists in a collection might include:
indexOf()
: A method on arrays that returns the index of the first occurrence of the specified element, or -1 if it's not found.in
operator: Can be used to check if an element is present in an array using for...in
loops (although this approach can be slower than others).However, these alternatives might not offer the same performance benefits as Map.has()
for large datasets.
I hope this explanation helps!