var a = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
var b = new Set(a)
return a.includes(3)
return b.has(3)
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
array.includes | |
set.has |
Test name | Executions per second |
---|---|
array.includes | 72342520.0 Ops/sec |
set.has | 1617207936.0 Ops/sec |
Let's break down the provided benchmark and explain what's being tested.
Benchmark Overview
The benchmark is designed to compare two approaches for checking if an element exists in a data structure:
includes
method)has
method)Script Preparation Code
The script preparation code creates two data structures: a
(an array) and b
(a Set, initialized with the elements of a
). This sets up the test environment for both scenarios.
var a = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
var b = new Set(a);
Options Compared
The benchmark compares two options:
includes
method: This checks if the specified element (3
) exists in the array a
.has
method: This checks if the specified element (3
) exists in the Set b
.Pros and Cons of Each Approach:
Array includes
method:
Pros:
Cons:
Set has
method:
Pros:
Cons:
Library Used:
The benchmark uses the built-in Set
and array methods (includes
, has
) without any external libraries.
Special JS Features or Syntax:
None mentioned. Both scenarios use standard JavaScript features.
Alternatives:
Other alternatives for checking if an element exists in a data structure include:
For this specific benchmark, the Set has
method is likely preferred due to its performance advantages. However, for more complex use cases or browsers that don't support Sets, the array includes
method may still be a viable option.