Benchmark: symmetric difference of sets

Tests:

Direct approach
a = ['a', 'b', 'c', 'd'] b = ['a', 'b', 'e', 'f'] let xor = a => b => [...a, ...b].filter(x => a.includes(x) ^ b.includes(x)) c = xor(a)(b)
Using diff(union)(inter)
a = ['a', 'b', 'c', 'd'] b = ['a', 'b', 'e', 'f'] let inter = a => b => a.filter(x => b.includes(x)) let union = a => b => [...a, ...b] let diff = a => b => a.filter(x => !b.includes(x)) let xor = a => b => diff(union(a)(b))(inter(a)(b)) c = xor(a)(b)
Using union(diff)(diff)
a = ['a', 'b', 'c', 'd'] b = ['a', 'b', 'e', 'f'] let union = a => b => [...a, ...b] let diff = a => b => a.filter(x => !b.includes(x)) let xor = a => b => union(diff(a)(b))(diff(b)(a)) c = xor(a)(b)

Rendered benchmark preparation results:

Previous results

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Latest run results:

Run details: (Test run date: one year ago)

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symmetric difference of sets (version: 0)