var a = "abcdefghijklmnopqrstuvwxyz";
Array.from(a).map(()=>a.toUpperCase());
Array.prototype.map.call(a,()=>a.toUpperCase());
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
Array.from->map | |
Array.prototype.map.call |
Test name | Executions per second |
---|---|
Array.from->map | 806951.2 Ops/sec |
Array.prototype.map.call | 550522.3 Ops/sec |
Let's dive into the explanation.
Benchmark Definition and Options Comparison
The provided benchmark compares two approaches to iterate over an array:
Array.from(a).map(() => a.toUpperCase())
Array.prototype.map.call(a, () => a.toUpperCase())
These two approaches aim to achieve the same result: converting the characters of the string "abcdefghijklmnopqrstuvwxyz" into uppercase using the toUpperCase()
method.
Approach 1: Using Array.from
and .map()
This approach uses the Array.from()
method to create a new array from the input string, followed by the .map()
method to apply the transformation function (a.toUpperCase()
) to each element in the array. The resulting array is then returned.
Pros:
Cons:
Array.prototype.map.call()
Approach 2: Using Array.prototype.map.call()
This approach uses the map()
method on the original string (wrapped in an array using Array.prototype.call()
), passing a callback function (a.toUpperCase()
) to apply the transformation. The resulting transformed array is returned.
Pros:
Cons:
Library and Special Features
None of the approaches rely on specific libraries or JavaScript features other than built-in methods (Array.from()
, map()
, .toUpperCase()
). No special features are used in these benchmarks.
Alternative Approaches
Other possible approaches could include:
String.prototype.toUpperCase()
directly on the input string, without creating an array: a.split('').map(c => c.toUpperCase()).join('')
for
-style iteration instead of .map()
However, these alternatives are not part of the original benchmark and would likely introduce additional overhead or complexity.
Benchmark Preparation Code
The preparation code creates an array from the string "abcdefghijklmnopqrstuvwxyz" using Array.from()
and assigns it to the variable a
. This setup ensures that both test cases have access to a valid input array.