var params = new Array(1000);let other = [];for (let x = 0; x < 100; ++x) { other = other.concat(params);}var params = new Array(1000);let other = [];for (let x = 0; x < 100; ++x) { other.push(params);}var params = new Array(1000);let other = [];for (let x = 0; x < 100; ++x) { other = [other, params];}--enable-precise-memory-info flag.
| Test case name | Result |
|---|---|
| concat | |
| push | |
| spread |
| Test name | Executions per second |
|---|---|
| concat | 64.1 Ops/sec |
| push | 146.8 Ops/sec |
| spread | 3.2 Ops/sec |
Let's break down the provided JSON and explain what is being tested, compared, and other considerations.
Benchmark Definition The benchmark definition specifies three different approaches to test:
other = other.concat(params)other.push(...params)other = [...other, ...params]These approaches are used to concatenate or merge two arrays: params and other. The number of elements in params is 1000.
Library Usage None of the provided benchmark definitions use any external libraries.
Special JS Features/Syntax
The only special syntax used in these tests is array spreading (...) in the "Spread" test case. Array spreading allows creating a new array by taking all elements from an existing array and adding them to it.
Let's analyze each approach:
=) to concatenate other with params. The result is stored back in other. This method can be more efficient because it avoids creating a new array, but it may lead to performance issues if the arrays are large.push() method to add all elements from params to other. This creates a new array and copies the data. While this is more straightforward, it can be slower than chaining because of the overhead of creating a new array....) to create a new array by taking all elements from both other and params. This method is concise but may lead to performance issues if the arrays are very large.Other Considerations
concat() and push() methods can be influenced by the browser's optimization techniques.Alternatives
There are other ways to concatenate arrays in JavaScript:
Array.prototype.reduce() method: other = other.reduce((acc, x) => acc.concat(x), params)for loop and push() method: for (let i = 0; i < params.length; i++) { other.push(params[i]); }However, the spread operator (...) is generally considered the most concise and efficient way to create a new array by concatenating two arrays.
