var values = new Array(5000);
for (let i = 0; i < values.length; ++i) {
values[i] = i % 20;
}
return Math.max(values);
return values.reduce((prev, curr) => {
if (curr > prev) return curr;
return prev;
}, 0);
let biggest = values[0];
for (let value of values) {
if (value > biggest) biggest = value;
};
return biggest;
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
Math.max | |
Reduce | |
for element of array |
Test name | Executions per second |
---|---|
Math.max | 79026.2 Ops/sec |
Reduce | 185638.4 Ops/sec |
for element of array | 210109.9 Ops/sec |
Let's break down the provided benchmark definition and test cases.
Benchmark Definition
The benchmark measures the speed of three different approaches to find the maximum value in an array:
Math.max()
: This function takes an array as an argument and returns the highest value in the array.Array.reduce()
: This method applies a reduction operation to the array, which is a way to combine all elements into a single output value. In this case, it finds the maximum value by comparing each element with the previous result.for
loop: A traditional for loop that iterates over the array and keeps track of the maximum value found so far.Options Compared
The benchmark compares the speed of these three approaches:
Math.max()
: a built-in JavaScript functionArray.reduce()
: a built-in JavaScript methodfor
loop: a traditional, iterative approachPros and Cons
Here's a brief summary of each approach:
Math.max()
: fast and concise, but may not be as efficient for very large arrays.Array.reduce()
: flexible and expressive, but may have performance overhead due to function call overhead.for
loop: straightforward and efficient, but requires manual bookkeeping of indices and comparisons.Library Used
The test cases use the following libraries:
None. The test cases only rely on built-in JavaScript methods and features.
Special JS Features/Syntax
There is no special JavaScript feature or syntax used in this benchmark.
Other Considerations
When choosing an approach, consider the trade-offs between speed, memory consumption, and readability. If you need a simple, fast solution for small to medium-sized arrays, Math.max()
might be a good choice. For more complex reduction operations or very large arrays, Array.reduce()
or a traditional for
loop might be more suitable.
Alternatives
If you're interested in exploring other alternatives, consider the following:
Math.min()
instead of Math.max()
for an opposite operation.Integer.MAX_VALUE
to find the maximum value.Keep in mind that the best approach will depend on your specific use case and performance requirements.