var string = ' ';
var regPattern = new RegExp(/\A\s*\z/g);
regPattern.test(string)
string.trim().length === 0
/^\s*$/.test(string)
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
regex | |
trim | |
regex new init every time |
Test name | Executions per second |
---|---|
regex | 6483915.5 Ops/sec |
trim | 12761210.0 Ops/sec |
regex new init every time | 9557902.0 Ops/sec |
Let's break down the provided JSON data and explain what's being tested, compared, and the pros/cons of each approach.
Benchmark Definition
The benchmark measures the performance of two approaches to remove whitespace from a string:
regPattern
)trim()
method/^\\s*$/.test(string)
)The purpose of this benchmark is to compare the performance of these three approaches, which are common techniques for removing whitespace from strings in JavaScript.
Options Compared
Here's a brief summary of each option:
\\s*
) at the start and end of the string (^
and $
). The g
flag at the end makes the match global, so it finds all occurrences in the string.Pros and Cons
Here are some pros and cons of each approach:
trim()
due to the overhead of compiling a regular expression pattern. Also, it's less efficient when dealing with large strings or many whitespace characters.trim()
and regPattern
due to compilation overhead.Library and Special JS Features
There is no library explicitly mentioned in the benchmark definition. However, it's worth noting that some JavaScript engines (like V8 in Chrome) have built-in optimizations for regular expressions, which can affect performance.
Other Considerations
When writing a benchmark like this, you should also consider:
Alternatives
Other alternatives for removing whitespace from strings in JavaScript include:
replace()
or split()
trim()
functionThese alternatives may have different trade-offs in terms of performance, complexity, and customization options.