const arr = new Array(10000).fill(Math.floor(Math.random() * 1000));
const s = new Set(arr);
for (let i = 0; i < arr.length; i++) {
const idx = arr.indexOf(i);
if (i !== -1) {
arr.splice(idx, 1);
}
}
const arr = new Array(10000).fill(Math.floor(Math.random() * 1000));
const s = new Set(arr);
for (let i = 0; i < arr.length; i++) {
if (s.has(i)) {
s.delete(i);
}
}
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
array | |
set |
Test name | Executions per second |
---|---|
array | 25.3 Ops/sec |
set | 6684.9 Ops/sec |
Benchmark Overview
The provided JSON represents a benchmark test on MeasureThat.net, which compares the performance of two approaches for removing elements from an array and a Set data structure in JavaScript.
Test Cases
There are two individual test cases:
indexOf()
, and removes the element from the array using splice()
if the index is valid.has()
method to check if each element exists in the Set before deleting it using delete()
.Comparison
The benchmark compares the performance of these two approaches under various browsers (Chrome 88) on different devices (Desktop) and operating systems (Windows).
Options Compared
Two options are compared:
splice()
method to remove elements from the array.delete()
method to remove elements from the Set.Pros and Cons of Each Approach
indexOf()
and splice()
)indexOf()
has()
and delete()
has()
and delete()
)Library Used
The Set data structure is a built-in JavaScript data type that stores unique values. It provides fast lookup, insertion, and deletion operations.
Special JS Features or Syntax
Neither of these approaches uses special JS features or syntax. They rely on standard JavaScript methods and syntax.
Other Considerations
When choosing between the Array approach and the Set approach, consider the following:
Alternatives
Other alternatives for removing elements from an array or set include:
filter()
or map()
to create a new array with the desired elements.reduce()
to iterate through the array and accumulate the results in a new array.Keep in mind that each alternative has its own trade-offs, such as additional memory usage or computational complexity.