var a = ['test'];
var b = ['testier'];
`${a[0]}${b}`
a[0].concat(b);
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
Interpolation | |
Concat |
Test name | Executions per second |
---|---|
Interpolation | 3296793.5 Ops/sec |
Concat | 3075954.8 Ops/sec |
Let's dive into the world of JavaScript microbenchmarks on MeasureThat.net.
The provided JSON represents a benchmark test for measuring the performance difference between two approaches: string interpolation and concatenation.
Script Preparation Code
Before running the benchmarks, the script prepares two arrays:
var a = ['test']; // array 'a'
var b = ['testier']; // array 'b'
This code sets up the input data for both test cases. The purpose of a
and b
is to create a string interpolation scenario.
Html Preparation Code
There is no HTML preparation code provided, so we can assume that this benchmark focuses solely on JavaScript performance.
Benchmark Definition
The JSON defines two benchmark test cases:
"${a[0]}${b}"
This benchmark tests the performance of string interpolation. The template literal syntax ("..."
) is used to insert the values from a
and b
into a single string. This approach is often faster because it avoids creating intermediate strings.
a[0].concat(b);
This benchmark tests the performance of concatenating two arrays using the concat()
method. This approach creates an intermediate string, which can lead to slower performance compared to interpolation.
Options Compared
The two test cases compare the following options:
"${a[0]}${b}"
)concat()
method (a[0].concat(b)
)Pros and Cons of Each Approach:
concat()
method:Library or Special JS Feature
There is no library used in this benchmark, but it does utilize a special JavaScript feature: template literals ("..."
). Template literals were introduced in ECMAScript 2015 (ES6) and provide a concise way to insert values into strings.
Other Alternatives
If you'd like to test other approaches or variations of these tests, consider adding more benchmark definitions. Some alternatives could be:
String.prototype.concat()
instead of the array's concat()
method.Feel free to ask if you have any further questions!