var a = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
return a.includes(9)
var b = new Set(a)
return b.has(9)
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
includes | |
convert to set |
Test name | Executions per second |
---|---|
includes | 89467664.0 Ops/sec |
convert to set | 7958976.5 Ops/sec |
Overview of the Benchmark
The provided benchmark measures the performance difference between two approaches: using array.includes()
and converting an array to a set with set.has()
. This test helps determine which method is faster for this specific use case.
Options Compared
Two options are compared:
array.includes()
: This approach involves searching for a specific value in the original array.set.has()
: This approach involves converting the array to a set, which automatically removes duplicates, and then checking if the desired value is present in the set.Pros and Cons of Each Approach
array.includes()
:set.has()
:Library Used
The Set
object is used as part of this benchmark. A Set
in JavaScript is an unordered collection of unique values, which can be used to store and look up elements efficiently.
Special JS Feature or Syntax
None mentioned in the provided code snippet. However, note that sets are a built-in JavaScript data structure since ECMAScript 5 (released in 2009), so no special features or syntax are required to use them.
Other Considerations
This benchmark measures performance specifically for searching an array for a single value using includes()
versus converting the array to a set and checking for presence with has()
. Other factors that might influence the choice of approach include:
Alternatives
If you need to perform similar searches or operations on arrays, consider exploring other approaches, such as:
find()
or findIndex()
methods with a callback function.Keep in mind that the choice of approach depends on your specific requirements and constraints.