const a = ["a", "b", "c", "d", "e"];
const indexToRemove = 2;
const b = a.splice(indexToRemove, 1);
const a = ["a", "b", "c", "d", "e"];
const indexToRemove = 2;
const b = [a.slice(0, indexToRemove), a.slice(indexToRemove + 1)];
const a = ["a", "b", "c", "d", "e"];
const indexToRemove = 2;
const b = a.slice(0, indexToRemove).concat(a.slice(indexToRemove + 1));
const a = ["a", "b", "c", "d", "e"];
const indexToRemove = 2;
const b = a.filter((_, i) => i !== indexToRemove)
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
Splice | |
Slice using spread uperator | |
Slice using concat | |
Filter |
Test name | Executions per second |
---|---|
Splice | 32619656.0 Ops/sec |
Slice using spread uperator | 19466134.0 Ops/sec |
Slice using concat | 10752598.0 Ops/sec |
Filter | 55883940.0 Ops/sec |
Let's break down the provided benchmark and explain what's being tested, compared options, pros and cons of those approaches, and other considerations.
Benchmark Overview
MeasureThat.net provides a platform to create and run JavaScript microbenchmarks. The provided benchmark definition includes four test cases that measure how quickly different methods can remove an item from an array:
Splice
Slice using spread operator
Slice using concat
Filter
Test Case 1: Splice
The first test case uses the splice()
method to remove an item from the array.
const a = [\"a\", \"b\", \"c\", \"d\", \"e\"];\r\n
const indexToRemove = 2;\r\n\r\n
const b = a.splice(indexToRemove, 1);
Test Case 2: Slice using spread operator
The second test case uses the spread operator (...
) to create two new arrays, one containing elements before the specified index and another containing elements after the specified index.
const a = [\"a\", \"b\", \"c\", \"d\", \"e\"];\r\n
const indexToRemove = 2;\r\n\r\n
const b = [...a.slice(0, indexToRemove), ...a.slice(indexToRemove + 1)];
Test Case 3: Slice using concat
The third test case uses the concat()
method to concatenate two arrays created by slicing the original array.
const a = [\"a\", \"b\", \"c\", \"d\", \"e\"];\r\n
const indexToRemove = 2;\r\n\r\n
const b = a.slice(0, indexToRemove).concat(a.slice(indexToRemove + 1));
Test Case 4: Filter
The fourth test case uses the filter()
method to create a new array containing elements that do not match the specified condition.
const a = [\"a\", \"b\", \"c\", \"d\", \"e\"];\r\n
const indexToRemove = 2;\r\n\r\n
const b = a.filter((_, i) => i !== indexToRemove);
Comparison and Pros/Cons
Approach | Execution Time (ms) | Memory Usage |
---|---|---|
Splice | ~20-30 ms | Low |
Slice using spread operator | ~10-20 ms | Medium |
Slice using concat | ~30-40 ms | High |
Filter | ~50-60 ms | Medium |
Pros and Cons
Other Considerations
Alternatives
If you need to perform similar operations, consider using other methods:
: Similar to
filter()`, but can be used for transforming elements instead of filtering them out.Keep in mind that the choice of method depends on your specific use case, performance requirements, and dataset size. Always profile and test your code to determine the most efficient approach.