Run results for: looking up the last character of a string - MeasureThat.net

Run details:

User agent: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/125.0.0.0 Safari/537.36

Browser: Chrome 125

Operating system: Windows

Device Platform: Desktop

Date tested: 6 months ago

Test name	Executions per second
short endsWith	18433988.0 Ops/sec
short regexp	8219703.5 Ops/sec
short charAt	9685357.0 Ops/sec
short brackets	9901799.0 Ops/sec
short CharCodeAt	10093338.0 Ops/sec
short slice	18124416.0 Ops/sec
short substr	17922024.0 Ops/sec
short substring	9876030.0 Ops/sec
long endsWidth	18529908.0 Ops/sec
long regexp	8375744.5 Ops/sec
long charAt	9885878.0 Ops/sec
long brackets	10084123.0 Ops/sec
long charCodeAt	10303986.0 Ops/sec
long slice	18120978.0 Ops/sec
long substr	18134594.0 Ops/sec
long substring	9552300.0 Ops/sec

Script Preparation code:

var shortString = 'okay'.repeat(20); // 80 characters
var longString = shortString.repeat(1000000); // 80,000,000 characters

var re = /\n$/;

Tests:

short endsWith
shortString.endsWith('\n');
short regexp
re.test(shortString)
short charAt
shortString.charAt(shortString.length-1)==='\n'
short brackets
shortString[shortString.length-1]==='\n'
short CharCodeAt
shortString.charCodeAt(shortString.length-1)===13
short slice
shortString.slice(-1)==='\n'
short substr
shortString.substr(-1)==='\n'
short substring
shortString.substring(shortString.length-1)==='\n'
long endsWidth
longString.endsWith('\n');
long regexp
re.test(longString)
long charAt
longString.charAt(longString.length-1)==='\n'
long brackets
longString[longString.length-1]==='\n'
long charCodeAt
longString.charCodeAt(longString.length-1)===13
long slice
longString.slice(-1)==='\n'
long substr
longString.substr(-1)==='\n'
long substring
longString.substring(longString.length-1)==='\n'