Run results for: looking up the last character of a string - MeasureThat.net

Run details:

User agent: Mozilla/5.0 (Macintosh; Intel Mac OS X 10_15_7) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/118.0.0.0 Safari/537.36

Browser: Chrome 118

Operating system: Mac OS X 10.15.7

Device Platform: Desktop

Date tested: one year ago

Test name	Executions per second
short endsWith	18253910.0 Ops/sec
short regexp	8110256.0 Ops/sec
short charAt	9356057.0 Ops/sec
short brackets	9294390.0 Ops/sec
short CharCodeAt	9808880.0 Ops/sec
short slice	16583537.0 Ops/sec
short substr	16457069.0 Ops/sec
short substring	8862557.0 Ops/sec
long endsWidth	16649596.0 Ops/sec
long regexp	8034733.0 Ops/sec
long charAt	9171561.0 Ops/sec
long brackets	9067296.0 Ops/sec
long charCodeAt	9789955.0 Ops/sec
long slice	16949260.0 Ops/sec
long substr	16767595.0 Ops/sec
long substring	8869425.0 Ops/sec

Script Preparation code:

var shortString = 'okay'.repeat(20); // 80 characters
var longString = shortString.repeat(1000000); // 80,000,000 characters

var re = /\n$/;

Tests:

short endsWith
shortString.endsWith('\n');
short regexp
re.test(shortString)
short charAt
shortString.charAt(shortString.length-1)==='\n'
short brackets
shortString[shortString.length-1]==='\n'
short CharCodeAt
shortString.charCodeAt(shortString.length-1)===13
short slice
shortString.slice(-1)==='\n'
short substr
shortString.substr(-1)==='\n'
short substring
shortString.substring(shortString.length-1)==='\n'
long endsWidth
longString.endsWith('\n');
long regexp
re.test(longString)
long charAt
longString.charAt(longString.length-1)==='\n'
long brackets
longString[longString.length-1]==='\n'
long charCodeAt
longString.charCodeAt(longString.length-1)===13
long slice
longString.slice(-1)==='\n'
long substr
longString.substr(-1)==='\n'
long substring
longString.substring(longString.length-1)==='\n'

;