Run results for: angular.copy vs JSON.parse(JSON.stringify()) vs angular.fromJson(angular.toJson())

FIguring out the performance differences between using the operations in the name on copying an array of objects considering the fact that other methods of copying (slice, concat, etc.) are shallow copies and end up being by reference instead of by value.

Go to the benchmark

Run details:

User agent: Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:99.0) Gecko/20100101 Firefox/99.0

Browser: Firefox 99

Operating system: Windows

Device Platform: Desktop

Date tested: 2 years ago

Test name	Executions per second
angular.copy()	753345.6 Ops/sec
JSON.parse(JSON.stringify())	360792.8 Ops/sec
_.colneDeep()	308008.1 Ops/sec
angular.fromJson(angular.toJson())	201224.5 Ops/sec

HTML Preparation code:

<html>
  <head>
  <script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.6.4/angular.min.js"></script>
  <script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.4/lodash.min.js"></script>
  </head>
  <body>
  </body>
</html>

Script Preparation code:

var origArr = [
 {
  name  : "obj1",
  val   : 1,
  color : "blue"
 },
  {
  name  : "obj2",
  val   : 2,
  color : "red"
 },
  {
  name  : "obj3",
  val   : 3,
  color : "green"
 },
  {
  name  : "obj4",
  val   : 4,
  color : "orange"
 }
];

var newArr = [];

Tests:

angular.copy()
newArr = angular.copy(origArr);
JSON.parse(JSON.stringify())
newArr = JSON.parse(JSON.stringify(origArr));
_.colneDeep()
newArr = _.cloneDeep(origArr);
angular.fromJson(angular.toJson())
newArr = angular.fromJson(angular.toJson(origArr));

Run results for: angular.copy vs JSON.parse(JSON.stringify()) vs angular.fromJson(angular.toJson())

FIguring out the performance differences between using the operations in the name on copying an array of objects considering the fact that other methods of copying (slice, concat, etc.) are shallow copies and end up being by reference instead of by value.

angular.copy()

JSON.parse(JSON.stringify())

_.colneDeep()

angular.fromJson(angular.toJson())