Run results for: LatLongDistance

Run details:

User agent: Mozilla/5.0 (Macintosh; Intel Mac OS X 10_12_6) AppleWebKit/605.1.15 (KHTML, like Gecko) Version/12.1.2 Safari/605.1.15

Browser: Safari 12

Operating system: Mac OS X 10.12.6

Device Platform: Desktop

Date tested: 3 years ago

Test name	Executions per second
full	316142.5 Ops/sec
quick	1951856.6 Ops/sec

Script Preparation code:

function getDistanceFromLatLonInKm2(lat, lng, lat0, lng0) {
  //https://jonisalonen.com/2014/computing-distance-between-coordinates-can-be-simple-and-fast/
  
  let deglen = 110.25
  let x = lat - lat0
  let y = (lng - lng0)*Math.cos(lat0)
  return deglen*Math.sqrt(x*x + y*y)
}

function getDistanceFromLatLonInKm(lat1, lon1, lat2, lon2) {
  var R = 6371; // Radius of the earth in km
  var dLat = deg2rad(lat2-lat1);  // deg2rad below
  var dLon = deg2rad(lon2-lon1); 
  var a = 
    Math.sin(dLat/2) * Math.sin(dLat/2) +
    Math.cos(deg2rad(lat1)) * Math.cos(deg2rad(lat2)) * 
    Math.sin(dLon/2) * Math.sin(dLon/2)
    ; 
  var c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1-a)); 
  var d = R * c; // Distance in km
  return d;
}

function deg2rad(deg) {
  return deg * (Math.PI/180)
}

Tests:

full
getDistanceFromLatLonInKm(51.496, -0.143, 51.601, -0.118);
quick
getDistanceFromLatLonInKm2(51.496, -0.143, 51.601, -0.118);

Run results for: LatLongDistance

full

quick