Run results for: looking up the last character of a string - MeasureThat.net

Run details:

User agent: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/91.0.0.0 Safari/537.36

Browser: Chrome 91

Operating system: Windows

Device Platform: Desktop

Date tested: 3 years ago

Test name	Executions per second
short endsWith	9466460.0 Ops/sec
short regexp	4825882.5 Ops/sec
short charAt	5522023.0 Ops/sec
short brackets	5547052.0 Ops/sec
short CharCodeAt	5548566.0 Ops/sec
short slice	11287434.0 Ops/sec
short substr	11312745.0 Ops/sec
short substring	5676787.5 Ops/sec
long endsWidth	9434316.0 Ops/sec
long regexp	4860472.5 Ops/sec
long charAt	5559106.0 Ops/sec
long brackets	5551017.5 Ops/sec
long charCodeAt	5556339.5 Ops/sec
long slice	11394167.0 Ops/sec
long substr	11330452.0 Ops/sec
long substring	5658648.5 Ops/sec

Script Preparation code:

var shortString = 'okay'.repeat(20); // 80 characters
var longString = shortString.repeat(1000000); // 80,000,000 characters

var re = /\n$/;

Tests:

short endsWith
shortString.endsWith('\n');
short regexp
re.test(shortString)
short charAt
shortString.charAt(shortString.length-1)==='\n'
short brackets
shortString[shortString.length-1]==='\n'
short CharCodeAt
shortString.charCodeAt(shortString.length-1)===13
short slice
shortString.slice(-1)==='\n'
short substr
shortString.substr(-1)==='\n'
short substring
shortString.substring(shortString.length-1)==='\n'
long endsWidth
longString.endsWith('\n');
long regexp
re.test(longString)
long charAt
longString.charAt(longString.length-1)==='\n'
long brackets
longString[longString.length-1]==='\n'
long charCodeAt
longString.charCodeAt(longString.length-1)===13
long slice
longString.slice(-1)==='\n'
long substr
longString.substr(-1)==='\n'
long substring
longString.substring(longString.length-1)==='\n'

;