var arr = []
let i = 0
let len = 1000
for(;i<len;i++) {
arr.push(i)
}
let i = 0
let len = arr.length
let foundIndex = -1
for(;i<len;i++) {
if (arr[i] > 999){
return i
}
}
const found = arr.find(function(element) {
return element > 999
})
let foundForEachIndex = -1
arr.forEach(function (item){
if (item[i] > 999){
foundForEachIndex = i
return
}
})
let foundMapIndex = arr.map(item => {
if (item[i] > 999){
return i
}
})
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
for | |
prototype.find | |
forEach | |
map |
Test name | Executions per second |
---|---|
for | 979191.9 Ops/sec |
prototype.find | 4385400.5 Ops/sec |
forEach | 37010.4 Ops/sec |
map | 35551.6 Ops/sec |
Let's break down the provided benchmark and explain what's being tested, compared options, pros and cons, and other considerations.
Benchmark Overview
The test aims to find the fastest way to search for an element in an array that exceeds 999 using different approaches: for
, prototype.find
, forEach
, and map
.
Options Compared
i
) and checks each element individually.find()
method, which calls the provided callback function once for each element in the array until it finds a match or reaches the end of the array.forEach
) and executes a callback function for each element.Pros and Cons
find()
method.prototype.find
due to unnecessary iterations.Library and Special Features
The test uses the find()
method on prototype objects, which is a built-in feature of JavaScript. It's available in modern browsers and Node.js environments.
The forEach
function also comes with JavaScript by default.
All these options are suitable for most use cases, but understanding their trade-offs can help optimize performance-critical code.
Other Alternatives
For similar searching scenarios:
prototype.find
, but returns the index of the first element that satisfies the condition instead of the element itself.Code Explanation
The provided benchmark code uses an array of 1000 elements and pushes numbers from 0 to 999 into it. Each test case uses a different method to find the index of the first element greater than 999:
i
, checks each element, and returns the index once found.find()
method to search for an element that satisfies the condition (arr[i] > 999
).forEach
, executes a callback function for each element, and updates a variable if it finds an element greater than 999.These different methods highlight their performance differences in finding specific elements within large arrays.
Benchmarking Considerations