const string = 'teste, teste, teste, teste'
const split = string.split(',');
const uniqueString = new Set(split);
if (uniqueString.size === 1) {
const uniqueStringResult = split[0];
}
const string = 'teste, teste, teste, teste'
const split = string.split(',');
if (split.every((splitItem) => splitItem === split[0])) {
const uniqueStringResult = split[0];
}
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
Set | |
Every |
Test name | Executions per second |
---|---|
Set | 6975116.0 Ops/sec |
Every | 18573202.0 Ops/sec |
The benchmark being tested in this case compares the performance of two different approaches to determine whether all elements in a split string are the same. The methods being compared are using the Set object and the every array method. Let's break down each approach and its implications.
Approach using Set
:
const split = string.split(','); const uniqueString = new Set(split); if (uniqueString.size === 1) { const uniqueStringResult = split[0]; }
split(',')
, then creates a new Set
from the resulting array. Sets ensure all values are unique, meaning if all elements are the same, the size of the set will be 1.Pros:
Set
collection automatically handles uniqueness, simplifying the logic required to determine if all elements are the same.Cons:
Set
is an additional overhead since it involves allocating memory for a new collection.Approach using every
:
const split = string.split(','); if (split.every((splitItem) => splitItem === split[0])) { const uniqueStringResult = split[0]; }
every
method.Pros:
every
method might be more straightforward in terms of logic because you're directly checking the condition you care about (uniformity among elements).Cons:
Set
.From the benchmark results:
Clearly, the every
method performs significantly better in this specific scenario, which is probably due to its lower overhead of not needing to instantiate a Set
.
When deciding between these approaches, consider the following:
There are alternative methods that were not tested here, such as:
reduce
to tally occurrences and determine if there is more than one unique string.Choosing the right method depends significantly on both performance needs and the specific use case, so engineers should benchmark their own solutions under realistic conditions to find the most suitable approach based on their unique requirements.