a = 999999999
b = 1000000000
c = (!(a % b))
c = a/b === Math.floor(a/b)
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
remainder | |
floor |
Test name | Executions per second |
---|---|
remainder | 2233707.2 Ops/sec |
floor | 1142198.1 Ops/sec |
Let's break down the provided JSON data and explain what's being tested in this JavaScript microbenchmark.
Benchmark Definition
The benchmark is designed to compare two approaches for integer division:
%
) to find the remainder of the division, which is then subtracted from the dividend (a
) to get the quotient.Math.floor()
function, which returns the largest integer less than or equal to the given number.Options Compared
The two options being compared are:
c = (!(a % b))
c = a/b === Math.floor(a/b)
Pros and Cons of Each Approach
Library and Special Features
There is no library explicitly mentioned in this benchmark. However, note that the Math.floor()
function is a built-in JavaScript function.
No special JavaScript features or syntax are being tested in this benchmark.
Other Alternatives
If you're looking for alternative approaches to integer division, consider:
>>
) to perform integer division without explicit division or remainder calculations.Keep in mind that these alternatives might not be as straightforward to implement and may have different performance characteristics compared to the original approaches being tested in this benchmark.
In summary, the provided JSON data represents a JavaScript microbenchmark comparing two approaches for integer division: Remainder and Subtraction versus Math.floor. The benchmark aims to determine which approach is faster, taking into account pros and cons of each method, as well as potential alternatives.