let array = new Array(1000000).fill(0);
array.push(1);
let array = new Array(1000000).fill(0);
array = [array, 1];
--enable-precise-memory-info
flag.
Test case name | Result |
---|---|
Array.push | |
Spread operator |
Test name | Executions per second |
---|---|
Array.push | 106.3 Ops/sec |
Spread operator | 87.0 Ops/sec |
Let's break down the provided benchmark and explain what is being tested.
What is being tested?
The benchmark measures the performance difference between using Array.push()
and the spread operator (...
) to add an element to an array of 1 million zeros. The test case has two variants:
push()
method to append a single element (1) to the end of the array....
) to create a new array with the original elements and then appends a single element (1) to it.Options compared
The two options being compared are:
Array.push()
: A method that adds one or more elements to the end of an array....
): A syntax for creating a new array by spreading elements from an existing array.Pros and cons of each approach
Array.push()
:...
):Array.push()
for large arrays, as it avoids creating a new internal array structure.Array.push()
, especially in older browsers.Library usage
There is no explicit library mentioned in the benchmark. However, both Array.push()
and the spread operator are built-in JavaScript methods that do not require any external libraries.
Special JS feature or syntax
None of the test cases use special JavaScript features or syntax beyond what's standard in modern JavaScript implementations.
Other alternatives
If you were to rewrite this benchmark, you could also compare other approaches, such as:
Array.prototype.concat()
: A method that creates a new array by concatenating two arrays.Array.prototype.set()
: A method that sets the elements of an array in place, which might be faster for large arrays but is less intuitive than push()
.Set
object instead of arrays: This approach would eliminate the need for arrays altogether and could potentially offer better performance.Keep in mind that these alternatives may not be suitable for all use cases, and the best approach depends on the specific requirements of your project.