Run results for: Check if point is on line two variants

Run details:

User agent: Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:68.0) Gecko/20100101 Firefox/68.0

Browser: Firefox 68

Operating system: Ubuntu

Device Platform: Desktop

Date tested: 4 years ago

Test name	Executions per second
new	29196980.0 Ops/sec
old	5072411.0 Ops/sec

Script Preparation code:

var sq = function (a) {
    return a * a;
};

function isOnLine1(p, v, w) {
    if (v[0] == w[0] && p[0] == v[0]
     || v[1] == w[1] && p[1] == w[1]
     || v[0] == w[0] && v[1] == w[1]) return true;
    var yDiff = Math.abs(p[1] - v[1] - (w[1] - v[1]) * ((p[0] - v[0]) / (w[0] - v[0])));
    var xDiff = Math.abs(p[0] - v[0] - (w[0] - v[0]) * ((p[1] - v[1]) / (w[1] - v[1])));

    var distance = yDiff < xDiff ? yDiff : xDiff; // off by a factor of at most ~0.707 = 1 / sqrt(2)
    return distance < 0.0017; // fp errors
}

function isOnLine2(p, v, w) {
    var distance = ((Math.abs((w[1] - v[1]) * p[0] -
        (w[0] - v[0]) * p[1] +
        w[0] * v[1] -
        w[1] * v[0])) /
        (Math.sqrt(sq(w[1] - v[1]) +
            sq(w[0] - v[0]))));
    return distance < 0.001; // fp errors
}
var a = false;

Tests:

new
a = isOnLine1([54.34523], [543.23], [123.3]);
old
a = isOnLine2([54.34523], [543.23], [123.3]);

Run results for: Check if point is on line two variants

new

old