var a = [1];
var b = new Set([1]);
var c = new Map([[1, 1]]);
return a.includes(1);
return b.has(1);
return c.has(1);
FAQ: FAQ
Source code: GitHub/MeasureThat.net
Report issues: MeasureThat.net/Issues
Based on: Benchmark.js
Facebook page: https://www.facebook.com/MeasureThat.Net
Python benchmarks support: Pyodide